Hi all, I'd like to construct a SQL statement for a search cursor using a LIKE with a wildcard instead of an =...but I'm having some difficulty as I find SQL in python with all it's backslashes, apostrophes, double quotes and escapes to be rather confusing. I don't know where to put the wildcard "%" and how to escape it in the code...
Here is what I've tried (couldn't get the script to work with "LIKE" but since I'm trying to find road names "LIKE" is necessary.
And this was provided to me on stackexchange but I haven't been able to implement a wildcard:
Here is what I've tried (couldn't get the script to work with "LIKE" but since I'm trying to find road names "LIKE" is necessary.
Code:
import arcpy
import os
import re
basedir = r"C:\Test"
fc = r"G:\GIS\ParcelsPublic.shp"
field1 = "ADD1"
field2 = "STREETNAME"
try:
for fn in os.listdir(basedir):
add = re.sub(r"\D"," ", fn)
add = str.lstrip(add)
add = str.upper(add)
street = re.sub(r"[^a-zA-Z]"," ",fn)
street = str.lstrip(street)
street = str.upper(street)
print (add + " " + street)
expression = '"' + field1 + '"= ' + "'%s'" %add
expression2 = '"' + field2 +'"= ' + "'%s'" %street
expression3 = expression + " "+ "AND" +" " + expression2
rows = arcpy.SearchCursor(fc, fields="STREETNAME; ARN; ADD1", where_clause=expression3)Code:
expression3 = '"{field1}" = \'{add}\' AND "{field2}" LIKE \'{street}\''.format(field1=field1, add=add, field2=field2, street=street)